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23 December, 16:39

Lindsay Electronics, a small manufacturer of electronic research equipment, has approximately 6 comma 500 items in its inventory and has hired Joan Blasco-Paul to manage its inventory. Joan has determined that 11 % of the items in inventory are A items, 33 % are B items, and 56 % are C items. She would like to set up a system in which all A items are counted monthly (every 20 working days), all B items are counted quarterly (every 62 working days), and all C items are counted semiannually (every 121 working days). How many items need to be counted each day? The total number of items that need to be counted each day is nothing items (round your response to the nearest whole number).

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  1. 23 December, 16:51
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    The total number of items to be counted each day ≈ 100

    Step-by-step explanation:

    Lindsay Electronics has 6,500 items in its inventory.

    11 % of the items in inventory are A items

    33% of the items in inventory are B items

    56 % of the items in inventory are C items

    A items are counted every 20 working days

    B items are counted every 62 working days

    C items are counted every 121 working days

    How many items need to be counted each day?

    First we will find the number of items of type A, B and C

    Number of A items = 11 % of 6,500 = 0.11*6500 = 715

    Number of B items = 33% of 6,500 = 0.33*6500 = 2145

    Number of C items = 56% of 6,500 = 0.56*6500 = 3640

    The number of A items to be counted each day is

    A items = 715/20

    The number of B items to be counted each day is

    B items = 2145/62

    The number of C items to be counted each day is

    C items = 3640/121

    The total number of items to be counted each day is

    Total items = 715/20 + 2145/62 + 3640/121

    Total items = 100.42

    Rounding the answer to the nearest whole number yields,

    Total items ≈ 100
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