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1 September, 13:02

For an arithmetic sequence that sums to 1485 it is known that the first term equals 6 and the last term equals 93 algebraically determine the number of terms summed in this series

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  1. 1 September, 13:15
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    30

    Step-by-step explanation:

    s_{n}=/frac{a+l}{2}=n

    first term=a

    last term=l

    number of terms=n

    1485=/frac{6+93}{2}n

    99 n=1485*2=2970

    n=2970/99=270/9=30

    number of terms=30
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