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12 May, 09:42

How many five-digit codes can be made if the first number cannot be a 0 or a 1 and no numbers can repeat?

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  1. 12 May, 10:06
    0
    24,192.

    Step-by-step explanation:

    The first number must be one of 2,3,4,5,6,7,8 or 9. That is 8 possibilities.

    The number of permutations of the other 4 numbers is 9P4

    = 9! / (9-4) !

    = 3024

    Now we multiply by the 8:

    3024 * 8

    = 24,192.
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