The square of a number is equal to 10 less than 7 times that number. What are two possible solutions

Question

Alan Murillo

Mathematics

31 December, 20:47

The square of a number is equal to 10 less than 7 times that number. What are two possible solutions

+4

Answers (1)

Know the Answer?

Cold Front · Answer 1

Answer:y=2 or 5

Step-by-step explanation:

let the number be y

y^2=7y-10

y^2-7y+10=0

y^2-2y-5y+10=0

y (y-2) - 5 (y-2) = 0

(y-2) (y-5) = 0

y-2=0 y-5=0

y=2 y=5