Find the relative minimum of

y = 3x^3 + 14x^2 - 11x - 46

(_, _)

Question

Fleming

Mathematics

1 June, 11:19

Find the relative minimum of

y = 3x^3 + 14x^2 - 11x - 46

(_, _)

+1

Answers (1)

Know the Answer?

Spencer Hurley · Answer 1

(0.353, - 48)

Step-by-step explanation:

dy/dx = 9x² + 28x - 11 = 0

Using the quadratic formula:

x = - 3.46 and 0.353

d²y/dx² = 18x + 28

Minima when d²y/dx² is positive

x = 0.35284 or (-14+sqrt (295)) / 9

y = 3x³ + 14x² - 11x - 46

y = - 48.00651351

Find the relative minimum ofy = 3x^3 + 14x^2 - 11x - 46(___, ___)

Find the relative minimum of

y = 3x^3 + 14x^2 - 11x - 46

(_, _)