Log3x + log3 (x2 + 2) = 1 + 2log3x

Question

Janiyah Grimes

Mathematics

19 January, 13:16

Log3x + log3 (x2 + 2) = 1 + 2log3x

+2

Answers (1)

Know the Answer?

Micheal Ross · Answer 1

x = 1, 2.

Step-by-step explanation:

I am assuming these are logs to the base 3.

log3 x + log3 (x^2 + 2) = 1 + 2log3x

-log3 x + log3 (x^2 + 2) = 1

log3 [ (x^2 + 2) / x] = 1 NOTE: 1 = log3 3, so:

log3 [ (x^2 + 2) / x] = log3 3

(x^2 + 2) / x = 3

x^2 - 3x + 2 = 0

(x - 1) (x - 2) = 0

x = 1, 2.