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15 January, 00:16

The equation of line k is y=-1/5x - 1/8. What is the equation of the line that is perpendicular to line k and passes through (0,0) ?

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  1. 15 January, 00:29
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    Y=-1/5 x-1/8

    Gradient, m = - 1/5

    A line perpendicular will be;

    m=15

    y=mx+c

    Replacing for x and y;

    0=5 (0) + c

    c=0

    y=5x
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