What is the sum of the first 100 positive multiples of 4?

sum = (n/2) (a+b) in which n=number of multiples a = value of first multiple b = value of last multiple So : (100/2) X (4+400) 50 X 404 20200 The final answer is 20200. You got it?

This would be a series: 5 + 10 + 15 + 20 + ... + 500

there are n terms → n = 100

the nth term is 500