In 1988,

Anthony Thornton walked backward

around Minneapolis, Minnesota,

for 24.46 hours. If his average speed

was 3.9 miles per hour, about how

many miles did he cover walking

backward?

Question

Natasha Kelley

Mathematics

6 June, 01:59

In 1988,

Anthony Thornton walked backward

around Minneapolis, Minnesota,

for 24.46 hours. If his average speed

was 3.9 miles per hour, about how

many miles did he cover walking

backward?

+3

Answers (2)

Know the Answer?

Demarion Bartlett · Answer 1

95.394 miles.

Step-by-step explanation:

Given:

Speed of movement, V = 3.9 mph

Time taken, t = 24.46 hours

Speed, V = Distance, D/time, t

Distance, D = 3.9 * 24.46

= 95.394 miles.

Koba · Answer 2

Answer: 95.4 miles

Step-by-step explanation:

Time taken for walk is 24.46 hours. Average speed for walk = 3.9 miles per hour

Recall that Distance = (Average Speed x Time taken)

So Distance = 3.9 miles per hour x 24.49 hours = 95.4 miles

Thus, Anthony covered 95.4 miles walking

backward from Minneapolis Minnesota

In 1988,Anthony Thornton walked backwardaround Minneapolis, Minnesota,for 24.46 hours. If his average speedwas 3.9 miles per hour, about howmany miles did he cover walkingbackward?

In 1988,

Anthony Thornton walked backward

around Minneapolis, Minnesota,

for 24.46 hours. If his average speed

was 3.9 miles per hour, about how

many miles did he cover walking

backward?