40% of OatyPop cereal boxes contain a prize. Hannah plans to keep buying cereal until she gets a prize. What is the probability that Hannah only has to buy 3 or less boxes before getting a prize? Use the simulation data to find the problability

the probability is 78.4%

Step-by-step explanation:

there are 3 scenarios

1) gets the price in the 1st box:

the probability is:

P = probability to obtain a price = 4/10 = 40%

2) gets the price in the 2nd box

P = probability to fail in the fist box * probability to obtain a price

P = (6/10) * (4/10) = 24/100 = 24%

3) gets the price in the 3rd box

P = probability to fail in the first box * probability to fail in the second box*probability to obtain a price = (6/10) * (6/10) * (4/10) = 144/1000 = 14,4%

therefore the probability to obtain a price in 3 or less boxes is:

P = 40%+24%+14.4% = 78.4%

86%

Step-by-step explanation:

I honestly don't know how its right but I'm positive it is i just guessed it on the I-ready lesson and got it right so It's definitely 86%