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3 January, 10:57

Solve the inequality. 3 divided by 10 is greater than or equal to k minus the quantity 3 divided by 5 end of quantity

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  1. 3 January, 11:22
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    Inequality:

    (3/10) ≥ k - (3/5)

    Add 3/5 to both sides:

    k ≤ (3/10) + (3/5)

    Use LCD:

    k ≤ (3/10) + (6/10)

    Combine:

    k ≤ 9/10
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