Use the discriminant to determine how many real number solutions exist for the quadratic equations - 4j+3j-28=0

The problem corrected is the following

4j^2+3j-28=0

In a quadratic equation

q (x) = ax^2 + bx + c

The discriminant is = b^2 - 4ac

If b^2 - 4ac > 0, then the roots are real.

If b^2 - 4ac < 0 then the roots are imaginary

In this problem

b^2 - 4ac = 3^2 - 4 (4) (-28) = 457

457>0 then the two roots must be real

For the quadratic equation there are two real solutions