Find the missing term (x^12) ^5 x (x^-2) ^9 x? = (x^40) ^5

Let the missing term be y

(x^12) ^5 x (x^-2) ^9 x y = (x^40) ^5

(x ∧60) x (x∧-18) x y = x∧200 (just multiply the powers together)

x∧60 : x∧18 x y = x∧200 (just put the x∧-18 as divider (is that what it called) and the power will be positive)

x∧42 x y = x∧200 (cross out the x∧18 by minusing power 60 by 18)

y = x∧200 : x∧42 (swapping the place)

y = x∧158