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Camilla Wu
Mathematics
14 March, 22:04
Solve sin 4x - cos 2x = 0.
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Jaiden Marshall
14 March, 22:15
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Sin 4 x - cos 2 x = 0
2 sin 2 x cos 2 x - cos 2 x = 0
cos 2 x (2 sin 2 x - 1) = 0
cos 2 x = 0
2 x = π/2 + nπ / : 2
x 1 = π/4 + nπ/2, n ∈ Z
2 sin 2 x - 1 = 0
2 sin 2 x = 1
sin 2 x = 1/2
2 x = π/6 + 2 nπ
2 x = 5π/6 + 2 nπ
x 2 = π/12 + nπ
x 3 = 5π/12 + nπ, n ∈ Z
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