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14 March, 22:04

Solve sin 4x - cos 2x = 0.

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  1. 14 March, 22:15
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    Sin 4 x - cos 2 x = 0

    2 sin 2 x cos 2 x - cos 2 x = 0

    cos 2 x (2 sin 2 x - 1) = 0

    cos 2 x = 0

    2 x = π/2 + nπ / : 2

    x 1 = π/4 + nπ/2, n ∈ Z

    2 sin 2 x - 1 = 0

    2 sin 2 x = 1

    sin 2 x = 1/2

    2 x = π/6 + 2 nπ

    2 x = 5π/6 + 2 nπ

    x 2 = π/12 + nπ

    x 3 = 5π/12 + nπ, n ∈ Z
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