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30 May, 06:39

The following data summarizes results from 941 pedestrian deaths that were caused by accidents. If one of the pedestrian deaths is randomly selected, find the probability that the pedestrian was intoxicated or the driver was intoxicated.

Pedestrian Pedestrian

Intoxicated Not intoxicated

Driver Intoxicated 56 71

Driver Not intoxicated 292 522

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  1. 30 May, 06:41
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    P=0.3698 or 36.98%

    Step-by-step explanation:

    Complete the table by adding the totals to each column and row.

    Pedestrian Pedestrian

    Intoxicated Not intoxicated Totals

    Driver Intoxicated 56 71 127

    Driver Not intoxicated 292 522 814

    Totals 348 593 941

    The probability that the pedestrian was intoxicated or the driver was intoxicated is the opposite event of neither of them was intoxicated. The total of cases when neither of them was intoxicated is 593. So the probability is:

    P1=593/941=0.6302

    The probability of the opposite event is one minus the probability calculated:

    P=1-0.6302=0.3698

    And this is the probability that the pedestrian was intoxicated or the driver was intoxicated.
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