Brad puts an equal amount of money in his savings account once a month. He started with $27. The next month he had $44 in his account. Two months after that he had $78 in his account. How much money will brad havr in his account after 6 months?

Question

Kayleigh Keith

Mathematics

28 November, 00:43

Brad puts an equal amount of money in his savings account once a month. He started with $27. The next month he had $44 in his account. Two months after that he had $78 in his account. How much money will brad havr in his account after 6 months?

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Answers (1)

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Ernesto Edwards · Answer 1

Answer: brad will have $112 in his account after 6 months.

Step-by-step explanation:

Since he puts equal amount of money in his savings account once a month, the rate at which the money is increasing is in arithmetic progression. The formula for determining the nth term of an arithmetic sequence is expressed as

Tn = a + (n - 1) d

Where

a represents the first term of the sequence.

d represents the common difference.

n represents the number of terms in the sequence.

From the information given,

a = $27

d = 44 - 27 = 17

n = 6 months

We want to determine the value of the 6th term, T6. Therefore,

T6 = 27 + (6 - 1) 17

T6 = 27 + 85

T6 = $112