Ask Question
1 February, 11:12

Find the lowest natural number which when divided by 12, 45, 15 and 10 leaves the remainder of

2 in each case.

+4
Answers (1)
  1. 1 February, 11:15
    0
    12=2*2*3

    45=3*3*5

    15=3*5

    10=2*5

    L. C. M=2*2*3*3*5=180

    required number 180+2=182
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Find the lowest natural number which when divided by 12, 45, 15 and 10 leaves the remainder of 2 in each case. ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers