Phyllis solved the compound inequality 16 < 2 (3x - 1) < 28. She began by first breaking the inequality into two separate inequalities, then she correctly solved each for x. 16 < 2 (3x - 1) and 2 (3x - 1) < 28 3 < x x < 5 Which graph represents her solution?

Question

Israel Hensley

Mathematics

11 October, 21:02

Phyllis solved the compound inequality 16 < 2 (3x - 1) < 28. She began by first breaking the inequality into two separate inequalities, then she correctly solved each for x. 16 < 2 (3x - 1) and 2 (3x - 1) < 28 3 < x x < 5 Which graph represents her solution?

+5

Answers (2)

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William Kaufman · Answer 1

16<2 (3x-1) <28 divide all terms by 2

8<3x-1<14 add 1 to all terms

9<3x<15 divide all terms by 3

3
x = (3,5) in interval notation

On a number line, it would be a line segment from 3 to 5 with open circles at 3 and 5.

On a coordinate system graph, it would be an infinitely high shaded plane between the vertical lines x=3 and x=5

Brody Lam · Answer 2

From question,

16<2 (3x-1) = 16<6x-2

=16+2<6x-2+2

=18<6x

=18/6<6x/6

=3
Again,

2 (3x-1) <28

=6x-2<28

=6x-2+2<28+2

=6x<30

=6x/6<30/6

=x<5

So both of ther graphs 3