A worker is being raised in a bucket lift at a constant speed of 3 ft/s. When the worker's arms are 10 ft off the ground, her coworker throws a measuring tape toward her. The measuring tape is thrown from a height of 6 ft with an initial vertical velocity of 15 ft/s. Projectile motion formula: h = - 16t2 + vt + h0 t = time, in seconds, since the measuring tape was thrown h = height, in feet, above the ground Which system models this situation? h = 3t+10 and h = - 16t2+15t+6 10t+3 and h = - 16t2+6t+15 - 16t2+3t + 10 and h = - 16t2+15t+6 - 16t2+10t + 3 and h = - 16t2+6t+15

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16 April, 18:14

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Adrianna Pitts · Answer 1

H=3t+10 and h=-16t+15t+6

They will never be at the same height at the same time