Two equations are given below:

a - 3b = 16

a = b - 2

What is the solution to the set of problems in the form (a, b) ?

a. (-2, - 6)

b. (-7, - 9)

c. (-11, - 9)

d. (-12, - 10)

You can solve this question by equating the two linear systems (by "substitution" or "elimination")

By substitution

-Take Equation 2 and substitute it in Equation 1

you will have (b-2) - 3b = 16 = > - 2b=18 = > b=-9

-Then, take b=-9 and substitute it in one of the equations (it doesn't really matter)

For eg substituting in equation 2 yields a=-11

Final ans: C where (a, b) is (-11,-9)