Given f (x) = 2x-1 and g (x) = x^2+7, find the following.

(f+g) (x)

(f-g) (x)

(f x g) (x)

(f/G) (x)

f[g (-8) ]

g[f (1) ]

(f+g) (x) = 2x - 1 + x^2 + 7 = x^2 + 2x + 6

(f-g) (x) = 2x - 1 - x^2 - 7 = - x^2 + 2x - 8

(f*g) (x) = (2x - 1) (x^2 - 7) = 2x^3 - 14x - x^2 + 7 = 2x^3 - x^2 - 14x + 7

(f/g) (x) = (2x - 1) / (x^2 - 7) - No simplification

f (g (-8)) = 2 ((-8) ^2) - 7) - 1

= 2 (64 - 7) - 1

= 2 (57) - 1 = 114 - 1 = 113

g (f (1)) = (2 (1) - 1) ^2 - 7

= (2 - 1) ^2 - 7

= 1^2 - 7 = 1 - 7 = - 6