What are the coordinates of the vertex of the function f (x) = x2+10x-3?

(-5, - 28)

(-5,28)

(5,-28)

(5, 28)

( - 5, - 28)

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a (x - h) ² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

To obtain this form use the method of completing the square

add/subtract (half the coefficient of the x - term) ² to x² + 10x

f (x) = x² + 2 (5) x + 25 - 25 - 3

= (x + 5) ² - 28 ← in vertex form

with (h, k) = ( - 5, - 28)

Vertex = ( - 5, - 28)