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28 November, 22:00

If 2 pipes are both open, they can fill a pool in 1 hour and 12 minutes. One of the pipes can fill the pool by itself in 2 hours. How long would it take the other pipe to fill the pool by itself?

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  1. 28 November, 22:01
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    Given both pipes can fill the pool in 1 h 12 mins = 72 mins

    Given one pipe can fill the pool in 2 h = 120 mins

    Let the other pipe fill the pool in x mins

    Pipe 1:

    120 mins = 1 pool

    1 min = 1/120 pool

    Pipe 2:

    x mins = 1 pool

    1 min = 1/x pool

    Both pipes need 72 mins to fill up the pool:

    72 (1/x + 1/120) = 1

    72 (x + 120) / 120x = 1

    72x + 8640 = 120x

    120x - 72x = 8640

    48x = 8640

    x = 180 mins = 3 hours

    Answer: It takes 3 hours for the other pipe to fill the pool.
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