12 September, 21:36
12 September, 21:56
First pull out the common factor of ab
ab (8a^3 + (1/125) b^3)
This is basically the sum of cubes. The linear factor is
(2a + 1/5 b)
The other factor is these two factors squared and their multiplicand subtracted.
(2a^2 - 2/5 ab + 1/25b^2)
Now put all this together and you get
ab (2a + 1/5 b) ((2a^2 - 2/5 ab + 1/25b^2)
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» 8a4b+1/125ab4 Factorise it