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22 December, 11:59

Events A and B are independent, Suppose event A occurs with probability 0.95 and event E occurs with probability 0.93.

a Compute the probability that neither the event A nor to event B occurs.

b Compute the probability that either B occurring A and B both occur.

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  1. 22 December, 12:11
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    a) 0.0035

    b) 0.93

    Step-by-step explanation:

    P (A) = 0.95

    P (E) = 0.93

    Now,

    P (A∩E) = P (A) * P (E) = 0.95 * 0.93

    or

    P (A∩E) = 0.8835

    P (A∪E) = P (A) + P (E) - P (A∩E)

    or

    P (A∪E) = 0.95 + 0.93 - 0.8835

    or

    P (A∪E) = 0.9965

    Therefore,

    a) probability that neither the event A nor to event B occurs

    P (A'∩E') = 1 - P (A∪E)

    or

    P (A'∩E') = 1 - 0.9965 = 0.0035

    b) probability that either B occurring A and B both occur

    P ((A'∩B) ∪ (A∩E)) = P (B) = 0.93
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