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12 August, 15:38

What the vertex and AOS if the equation is y = (x-2) ^2-2

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  1. 12 August, 15:57
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    See below.

    Step-by-step explanation:

    For y = a (x - b) ^2 + c, the vertex is at (b, c) and the axis of symmetry is x = b.

    So for y = (x-2) ^2 - 2,

    the vertex is (2, - 2) and the axis of symmetry is x = 2.
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