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28 August, 15:53

You are playing a dice game called Noluz against one other person. Each time you play, both players pay a quarter. You win the money if a 1 or 4 shows face up on the die. The other player wins if a 2 or 5 comes up, and the piggy bank gets the money if a 3 or 6 comes up. This money will then be donated to a charity that you pick. What is the expected value per turn for playing Noluz?

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  1. 28 August, 16:19
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    Assuming a fair die,

    probability of winning 0.25 = (2/6) = 1/3

    probability of losing 0.25 = (4/6) = 2/3

    Expected win

    = sum (proba.*winning)

    =0.25 * (1/3) + (-0.25) (2/3)

    =-0.25/3

    = - (1/12) dollars (negative sign means expecting to lose)
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