You are playing a dice game called Noluz against one other person. Each time you play, both players pay a quarter. You win the money if a 1 or 4 shows face up on the die. The other player wins if a 2 or 5 comes up, and the piggy bank gets the money if a 3 or 6 comes up. This money will then be donated to a charity that you pick. What is the expected value per turn for playing Noluz?

Question

Kamren Vazquez

Mathematics

28 August, 15:53

You are playing a dice game called Noluz against one other person. Each time you play, both players pay a quarter. You win the money if a 1 or 4 shows face up on the die. The other player wins if a 2 or 5 comes up, and the piggy bank gets the money if a 3 or 6 comes up. This money will then be donated to a charity that you pick. What is the expected value per turn for playing Noluz?

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Answers (1)

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Kian Gates · Answer 1

Assuming a fair die,

probability of winning 0.25 = (2/6) = 1/3

probability of losing 0.25 = (4/6) = 2/3

Expected win

= sum (proba.*winning)

=0.25 * (1/3) + (-0.25) (2/3)

=-0.25/3

= - (1/12) dollars (negative sign means expecting to lose)