A pair of dice is rolled. find the probability of rolling a sum between 3 and 8

It does not say is btw 3 and 8 inclusive so we can assume is sum 4,5,6, and 7

Sum 4 is made 1+3, 2+2

Sum 5 is made 1+4, 2+3

Sum 6 is made 1+5, 2+4, 3+3

Sum 7 is made 1+6, 2+5, 3+4

So there are 10 ways to make the sum 4,5,6,7

The total number of possible sums 10+11=21

Sum of 2 is 1+1

Sum of 3 is 1+2

Sum of 8 is 2+6, 3+5, 4+4

Sum of 9 is 3+6, 4+5

Sum of 10 is 4+6, 5+5

Sum of 11 is 5+6

Sum of 12 is 6+6

Probably = 10/21