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29 April, 18:43

Use d=1/2gt2 and solve for the time one spends moving upward in a 0.6-m vertical jump. Then double it for the "hang time"-the time one's feet are off the ground. Express your answer to two significant figures and include the appropriate units.

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  1. 29 April, 18:55
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    t = 0.35 seconds

    Step-by-step explanation:

    We have given the equation:

    d=1/2gt²

    where,

    g = 9.8 m/s²

    d = 0.6 m

    t = ?

    Now put the values in the given formula:

    d*2/g = t²

    0.6*2/9.8 = t²

    1.2/9.8 = t²

    0.12245 = t²

    Now find the square root of both sides

    √t² = √0.12245

    t = 0.35 seconds
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