The area of a triangle is 384 square feet. If its base is 8 feet longer than its altitude, find the length of the base and the altitude

A=1/2bh

b=8+h

A=384

384=1/2 (bh)

times 2

768=bh

sub

768=b (8+b)

768=8b+b^2

minus 768 both sides

0=b^2+8b-768

factor

0 = (b-24) (b+32)

set to zero

b-24=0

b=24

b+32=0

minus 32

b=-32

false, legnths cannot be negative

b=24

24=8+h

minus 8

16=h

base=24ft

altetude=16ft