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29 January, 20:47

You are planning to make an open rectangular box from a 33 -in.-by-65 -in. piece of cardboard by cutting congruent squares from the corners and folding up the sides. What are the dimensions of the box of largest volume you can make this way, and what is its volume?

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  1. 29 January, 20:48
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    Volume = 6783.27inch³

    H = 6.951inch

    L = 51.098inch

    W = 19.098inch

    Step-by-step explanation:

    From the given information:

    Let h = side length and height of the box

    L = length of the box

    W = width of the box

    V = volume of the box

    We have that:

    L = 65-2h

    W = 33-2h

    V = L*W*h

    Therefore we have

    V = (65-2h) (33-2h) * h

    V = (2145-130h-66h+4h²) * h

    V = 2145h-196h²+4h³

    By differentiating V w. r. t h, we have

    V' = 2145-392h+12h²

    V = 12h²-392h+2145

    Using Almighty formula we have

    h = 392+/-√392²-4 (12) (2145) / 2 (12)

    h = 6.951 or 25.716

    Thus, we find L, W and V.

    We use the least value of h in order not to get a negative value of volume, length and width

    L = 65-2h = 65-2 (6.951) = 51.098

    W = 33-2h = 33-2 (6.951) = 19.098

    V = LWH = 51.098*19.098*6.951 = 6783.2696inches
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