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29 November, 15:25

Write a quadratic function whose zeros are - 2 and - 10

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  1. 29 November, 15:33
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    f (x) = x^2 + 12x + 20

    Step-by-step explanation:

    What is meant is that write a function that when - 2 is put in for x, the function goes to 0.

    More formally f (-2) = 0.

    So the function you want is f (x) = y = (x + 2) (x + 10) which is

    f (x) = x^2 + 10x + 2x + 20

    f (x) = x^2 + 12x + 20

    Now put - 2 into this function.

    f (-2) = (-2) ^2 + 12 (-2) + 20

    f (-2) = 4 - 24 + 20

    f (-2) = 4 + 20 - 24

    f (-2) = 0

    I'll leave you to do the same thing with - 10
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