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19 March, 17:57

Three positive numbers are in the ratio 7:3:2. The sum of the smallest number to the largest number exceeds twice the remaining number by 30. Find the three numbers.

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  1. 19 March, 18:09
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    The numbers are 70,30,20.

    Step-by-step explanation:

    Let the three numbers be 7x, 3x and 2x.

    The sum of smallest and largest number is 7x+2x=9x.

    According to question:

    9x-30=2 (3x)

    Simplifying the equation:

    9x-30=6x

    Adding 30 both sides:

    9x=6x+30 or, 9x-6x=30

    3x=30, x=10,

    The numbers are 7x=7 (10) = 70

    3x=3 (10) = 30

    2x=2 (10) = 20.
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