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Keaton Mcbride
Mathematics
20 June, 10:26
The remainder when 2x^2-x-5 divided by (x-3) is
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Shaylee
20 June, 10:53
0
10
Step-by-step explanation:
2x^2-x-5 = 2x^2-6x + 5x - 15 + 10 = 2x (x-3) + 5 (x-3) + 10 = (2x+5) (x-3) + 10
(2x^2-x-5) / (x-3) = 2x+5 + 10 / (x-3)
So the remainder is 10
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