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24 October, 07:55

If t17 = 3 (t5) in an arithmetic progression, find t1 in terms of d.

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  1. 24 October, 08:16
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    t1 = 2d.

    Step-by-step explanation:

    The explicit formula for an arithmetic series is

    The nth term tn = t1 + d (n - 1) where t1 = the first term, d = common difference and n = term number.

    so t17 = t1 + 17d - d = t1 + 16d

    and t5 = t1 + 5d - d = t1 + 4d

    So t1 + 16d = 3 (t1 + 4d)

    2t1 = 16d - 12d = 4d

    t1 = 2d (answer).
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