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Pooky
Mathematics
26 November, 09:06
Find dydt for the equation below.
7x3+7y3=9
+1
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2
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Alexia Carpenter
26 November, 09:11
0
dy/dt = - x^2/y^2 dx/dt
Step-by-step explanation:
7x^3 + 7y^3 = 0
Take the derivative with respect to t
7 * 3x^2 dx/dt + 7 * 3y^2 dy/dt = 0
21 x^2 dx/dt + 21 y^2 dy/dt = 0
Divide each side by 21
x^2 dx/dt + y^2 dy/dt = 0
Subtract x^2 dx/dt from each side
x^2 dx/dt - x^2 dx/dt+y^2 dy/dt = - x^2 dx/dt
y^2 dy/dt = - x^2 dx/dt
Divide each side by y^2
y^2 / y^2 dy/dt = - x^2/y^2 dx/dt
dy/dt = - x^2/y^2 dx/dt
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Coy
26 November, 09:16
0
y=-1
Step-by-step explanation:
I thought the unknown space between 7y and 3 was multiplication so here is my work.
7*3+7y*3
21+7*-1*3
=9
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