Proof sin^3xcos^4x=sinx (cos^4x-cos^6x)

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Solomon Mcguire

Mathematics

24 November, 02:10

Proof sin^3xcos^4x=sinx (cos^4x-cos^6x)

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Brodie Good · Answer 1

Sin³ (x) cos⁴ (x) = sin (x) [cos⁴ (x) - cos⁶ (x) ]

sin (x) sin (x)

sin² (x) cos⁴ (x) = cos⁴ (x) - cos⁶ (x)

sin² (x) cos⁴ (x) = cos⁴ (x) [1] - cos⁴ (x) [cos² (x) ]

sin² (x) cos⁴ (x) = cos⁴ (x) [1 - cos² (x) }

cos⁴ (x) cos⁴ (x)

sin² (x) = 1 - cos² (x)

+ cos² (x) + cos² (x)

1 = 1