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9 May, 23:35

How would the expression x3 - 64 be rewritten using difference of cubes? A. (x + 4) (x2 - 4x - 16) B. (x - 4) (x2 + 4x + 16) C. (x + 4) (x2 - 4x + 16) D. (x - 4) (x2 + 16x + 4)

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Answers (2)
  1. 9 May, 23:38
    0
    B. (x - 4) (x2 + 4x + 16)

    Step-by-step explanation:

    a3 - b3 = (a - b) (a2 + ab + b2)

    substitute a=x n b=4 (cuz 64=4x4x4)

    x3 - 64 = (x-4) (x2+4x+4x4)

    = (x - 4) (x2 + 4x + 16)
  2. 9 May, 23:47
    0
    B. (x - 4) (x2 + 4x + 16)

    Step-by-step explanation:

    Difference of cubes can be rewritten as:

    a^3 - b^3 = (a - b) (a^2 + ab + b^2)

    So in this case, x^3 - 64 = x^3 - (4) ^3 where a = x and b = 4

    = (x-4) (x^2 + 4x + 4^2)

    = (x-4) (x^2 + 4x + 16)

    The answer is B.
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