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9 March, 03:38

If ab = 8 and a^2+b^2=16, then what is the value of (a+b) ^2?

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  1. 9 March, 04:01
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    Note that (a+b) ^2 = a^2 + 2ab + b^2. This is always true.

    Let's re-write the given " ab = 8 and a^2+b^2=16" as

    a^2 + 2ab + b^2 = 16 + 2ab, or, equivalently, as

    (a+b) ^2 = 16 + 2 (8) = 32.

    This is the answer we wanted.
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