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The sum of three consecutive integers is 141. what is the smallest integer

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  1. 30 May, 12:20
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    Integer 1 = n

    integer 2 = n + 1

    integer 3 = n + 2

    n + (n + 1) + (n + 2) = 141

    3n + 3 = 141

    3n = 141 - 3

    3n = 138

    n = 138/3

    n = 46 - - (1st integer)

    n + 1 = 46 + 1 = 47 - - (2nd integer)

    n + 2 = 46 + 2 = 48 - - (3rd integer)

    so the smallest integer is 46
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