Ask Question
26 December, 00:55

First, we need to find the radius: r = sqrt ((-3) ^2 + 1^2) = sqrt (10) sin (theta) = y/r = 1/sqrt (10) = sqrt (10) / 10 cos (theta) = x/r = - 3/sqrt (10) = - 3sqrt (10) / 10 tan (theta) = y/x = - 1/3

+3
Answers (1)
  1. 26 December, 01:24
    0
    r = sqrt (10) = sqrt (10) sin (0) = y/r = 1/sqrt (10) = (cos (0)) / sqrt (10) = x/r = - 3/sqrt (10) = - (3 tan (0)) / sqrt (10) = y/x = - 1/3.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “First, we need to find the radius: r = sqrt ((-3) ^2 + 1^2) = sqrt (10) sin (theta) = y/r = 1/sqrt (10) = sqrt (10) / 10 cos (theta) = x/r ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers