Subtract 9a^2-6a+59a 2 - 6a+59, a, squared, minus, 6, a, plus, 5 from 10a^2+3a+2510a 2 + 3a+2510, a, squared, plus, 3, a, plus, 25. Your answer should be a polynomial in standard form.

Question

Nichols

Mathematics

17 December, 23:43

Subtract 9a^2-6a+59a 2 - 6a+59, a, squared, minus, 6, a, plus, 5 from 10a^2+3a+2510a 2 + 3a+2510, a, squared, plus, 3, a, plus, 25. Your answer should be a polynomial in standard form.

+4

Answers (1)

Know the Answer?

Keira Conrad · Answer 1

The answer to your question is a² + 9a + 20

Step-by-step explanation:

10a² + 3a + 25 - (9a² - 6a + 5)

- Remove parentheses changing the sign of the second polynomial

10a² + 3a + 25 - 9a² + 6a - 5

- Group like terms

(10a² - 9a²) + (3a + 6a) + (25 - 5)

- Simplify and result

a² + 9a + 20