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3 January, 05:38

What is the surface area of a regular pentagonal prism with side length 8, altitue 20 and apothem approximately 5.5

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  1. 3 January, 05:59
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    The surface area of the pentagonal prism is given by:

    SA=2[area of the pentagonal sides]+5[area of rectangle sides]

    Area of pentagonal side will be given by:

    Area=5/2 sa

    where;

    side, s=8

    apothem, a=5.5

    hence;

    Area=5/2*8*5.5=110 sq units

    Area of rectangular side will be:

    Area=length*width

    =20*8=160 sq units

    therefore the surface area (SA) will be:

    SA=110*2+5*160

    =1,020 sq. units
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