Part 1 (Unit 2) : Subtract Polynomials:

(3-6n5-8n4) - (-6n4-3n-8n5)

Part 2 (Unit 3) : Solve this quadratic equation. Show all your work (steps) for full credit:

4x2-2x-5=0

Part 1

We have the following polynomials:

(3-6n5-8n4)

(-6n4-3n-8n5)

Subtracting the polynomials we have:

(3-6n5-8n4) - ( - 6n4-3n-8n5)

n5 (-6 + 8) + n4 (-8 + 6) + 3n + 3

Rewriting:

2n5 - 2n4 + 3n + 3

Part 2

For this case we have the following polynomial:

4x2-2x-5 = 0

Using resolver we have:

x = ( - b + / - root (b ^ 2 - 4 * a * c)) / (2 * a)

x = ( - ( - 2) + / - root (( - 2) ^ 2 - 4 * 4 * ( - 5))) / (2 * 4)

x = (2 + / - root (4 + 80)) / (8)

x = (2 + / - root (84)) / (8)

x = (2 + / - root (4 * 21)) / (8)

x = (2 + / - 2raiz (21)) / (8)

x = (1 + / - root (21)) / (4)

The roots are:

x1 = (1 + root (21)) / (4)

x2 = (1 - root (21)) / (4)