The scores on a standardized test are normally distributed with a mean of 500 and a standard deviation of 60. Jake scored 520 on the test. What percent of students scored below Jake? Include a step by step description of the process you used to find that percentage. (Round your answer to the nearest whole number.)

63 percent student scored below Jake.

Step-by-step explanation:

For finding the percentile

Step 1: Subtracting mean from Jake's score

=520-500

=20

Step 2: Calculating z-score

The z-Score is found by dividing the difference obtained in step 1 by SD of the data

z-score = 20/60

z-score=0.333

Step 3: Converting the z-score to percentile

The z-score will be converted to percentile using the z-score to percentile conversion table, the value of percentile for 0.3333 is 63rd.

So, 63 percent students scored below Jake.