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24 September, 18:40

The perimeter of a basketball court is 284 ft. the length is 40 ft longer than the width. find the dimensions of the court.

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  1. 24 September, 18:56
    0
    We know that the perimeter is the distance around an object. This is also 2 times the length + 2 times the width. We know the width would be X and the length would be 40 feet longer so it is x+40. Now we have 2 (X) + 2 (x+40) = 284

    Doing the distributive property you would get 2x + 2x + 80=284

    add like terms to get 4x+80=284

    subtract 80 from both sides to get 4x=204

    divide both sides by 4 to get x=51

    Width is 51 and width is 40 more than that so length is 91
  2. 24 September, 19:07
    0
    284=2x+2 (x+40)

    284=4x+80

    204=4x

    51=x

    dimensions 51 ft by 91ft
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