It takes the high-speed train x hours to travel the z miles from Town A to Town B at a constant rate, while it takes the regular train y hours to travel the same distance at a constant rate. If the high-speed train leaves Town A for Town B at the same time that the regular train leaves Town B for Town A, how many more miles will the high-speed train have traveled than the regular train when the two trains pass each other?

(A) z (y - x) / x + y

(B) z (x - y) / x + y

(C) z (x + y) / y - x

(D) xy (x - y) / x + y

(E) xy (y - x) / x + y

Question

Timber

Mathematics

8 September, 08:32

It takes the high-speed train x hours to travel the z miles from Town A to Town B at a constant rate, while it takes the regular train y hours to travel the same distance at a constant rate. If the high-speed train leaves Town A for Town B at the same time that the regular train leaves Town B for Town A, how many more miles will the high-speed train have traveled than the regular train when the two trains pass each other?

(A) z (y - x) / x + y

(B) z (x - y) / x + y

(C) z (x + y) / y - x

(D) xy (x - y) / x + y

(E) xy (y - x) / x + y

+5

Answers (1)

Know the Answer?

Tatum George · Answer 1

B

Step-by-step explanation:

To solve this, we use ratio.

Firstly, we need to know the number of hours traveled. The total number of hours traveled = x+y

Ratio of this used by high speed train = x / (x + y).

Total distance traveled before they meet = [x / (x + y) ] * z

For low speed train = [y / (x + y) ] * z.

The difference would be distance by high speed train - distance by low speed train.

= z [ (x - y) / x + y) ]