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Tobias Patton
Mathematics
9 July, 18:51
The antiderivative of
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Karly Owens
9 July, 18:59
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Sqrt y = y^1/2
antiderivative = 33 * y^ (1/2 + 1) / (1/2 + 1) = 33 * y^ (3/2) / 3/2
= 33 * 2/3 * y^ (3/2)
= 22 y^ (3/2) answer
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