A rectangular room is 6 6 meters longer than it is wide, and its perimeter is 28 28 meters. find the dimension of the room

We know that perimeter is equal to 2l+2w or l+l+w+w.

We also know that the length is 6 meters longer than the width.

Based on this we can create the following formula to find the dimensions:

28 = (w+6) + (w+6) + w+w

Then to solve, it's just simple algebra.

First, combine like terms: 28 = w+w+w+w+6+6 28 = 4w+12

The next thing we do is isolate the variable by subtracting 12 from each side: 28-12 = 4w+12-12 16 = 4w

The next thing we do is divide both sides by the coefficient (4) : 16/4 = 4w/4

And this gives us the answer that w=4.

Now to find the dimensions:

We know that the width is equal to 4.

We also know that the length is equal to 6 more than the width. If the width is 4 then the length is 4+6 or 10.

So there you have it, the dimensions of the room would be 4x10.