What are the first five terms of the sequence defined by the given function?

(1) = - 6

f (n) = f (n - 1) + 2, for n = 2, 3, 4, ...

ОА. 2, 8, 14, 20, 26

ов. 2, - 4, - 10, - 16, - 22

о с. - 6, - 4, - 2, 0, 2

O D. - 6, - 8. - 10, - 12, - 14

0

0

C) With the given general term, given sequence is - 6, - 4, - 2, 0, 2, ...

Step-by-step explanation:

Here, the first term f (1) = - 6

The general term of the sequence:

f (n) = f (n-1) + 2

Now, we find the next five terms from the given general term:

For n = 2 : f (2) = f (2-1) + 2

= f (1) + 2 = - 6 + 2 = - 4

⇒ f (2) = - 4

For n = 3 : f (3) = f (3-1) + 2

= f (2) + 2 = - 4 + 2 = - 2

⇒ f (3) = - 2

For n = 4 : f (4) = f (4-1) + 2

= f (3) + 2 = -2 + 2 = 0

⇒ f (4) = 0

For n = 5 : f (5) = f (5-1) + 2

= f (4) + 2 = 0 + 2 = 2

⇒ f (5) = 2

Hence with the given general term, given sequence is - 6, - 4, - 2, 0, 2, ...